A small electric dipole 𝑝 0, having a moment of inertia I about its center, is kept at a distance r from the center of a spherical shell of radius R. The surface charge density  is uniformly distributed on the spherical shell. The dipole is initially oriented at a small angle πœƒ as shown in the figure. While staying at a distance r, the dipole is free to rotate about its center. If released from rest, then which of the following statement(s) is(are) correct? [πœ€0 is the permittivity of free space.] (A) The dipole will undergo small oscillations at any finite value of r. (B) The dipole will undergo small oscillations at any finite value of r > R. (C) The dipole will undergo small oscillations with an angular frequency of √ 2πœŽπ‘0 πœ–0𝐼 at r = 2𝑅. (D) The dipole will undergo small oscillations with an angular frequency of √ πœŽπ‘0 100πœ–0𝐼 at r = 10R.

 To solve this problem, we need to analyze the behavior of a small electric dipole 

p0 placed near a uniformly charged spherical shell. The dipole is free to rotate about its center and is initially oriented at a small angle ΞΈ. We will determine the conditions under which the dipole undergoes small oscillations and calculate the angular frequency of these oscillations.


Step 1: Electric Field Due to the Spherical Shell

A uniformly charged spherical shell of radius R with surface charge density Οƒ produces an electric field. Outside the shell (r>R), the electric field is equivalent to that of a point charge at the center of the shell:

E=ΟƒR2Ο΅0r2

where:

  • Οƒ is the surface charge density,

  • R is the radius of the shell,

  • r is the distance from the center of the shell to the dipole,

  • Ο΅0 is the permittivity of free space.

Inside the shell (r<R), the electric field is zero due to the symmetry of the spherical shell.


Step 2: Torque on the Dipole

The dipole p0 experiences a torque Ο„ in the presence of the electric field E. The torque is given by:

Ο„=p0×E

For small angles ΞΈ, the magnitude of the torque is:

Ο„=p0EsinΞΈp0EΞΈ

Substituting the electric field E for r>R:

Ο„=p0(ΟƒR2Ο΅0r2)ΞΈ

Step 3: Equation of Motion

The torque causes the dipole to undergo rotational motion. The equation of motion for small oscillations is:

Id2ΞΈdt2=Ο„

Substituting the expression for Ο„:

Id2ΞΈdt2=p0(ΟƒR2Ο΅0r2)ΞΈ

This is a simple harmonic oscillator equation of the form:

d2ΞΈdt2+Ο‰2ΞΈ=0

where the angular frequency Ο‰ is:

Ο‰=p0ΟƒR2Ο΅0Ir2

Step 4: Analyzing the Statements

Now, let's analyze the given statements:

(A) The dipole will undergo small oscillations at any finite value of r.

  • This is incorrect because the dipole will only oscillate if r>R. For r<R, the electric field inside the shell is zero, and there is no torque to cause oscillations.

(B) The dipole will undergo small oscillations at any finite value of r>R.

  • This is correct because for r>R, the electric field is non-zero, and the dipole will experience a torque, leading to small oscillations.

(C) The dipole will undergo small oscillations with an angular frequency of 2Οƒp0Ο΅0I at r=2R.

  • Substituting r=2R into the expression for Ο‰:

    Ο‰=p0ΟƒR2Ο΅0I(2R)2=p0Οƒ4Ο΅0I

    This does not match the given frequency. Hence, this statement is incorrect.

(D) The dipole will undergo small oscillations with an angular frequency of Οƒp0100Ο΅0I at r=10R.

  • Substituting r=10R into the expression for Ο‰:

    Ο‰=p0ΟƒR2Ο΅0I(10R)2=p0Οƒ100Ο΅0I

    This matches the given frequency. Hence, this statement is correct.


Final Answer:

The correct statements are:

(B) and (D)

0 Comments

Post a Comment

Post a Comment (0)

Previous Post Next Post